F(x)=5x^2+8x-300

Solution for F(x)=5x^2+8x-300 equation:

(F)=5F^2+8F-300

We move all terms to the left:

(F)-(5F^2+8F-300)=0

We get rid of parentheses

-5F^2+F-8F+300=0

We add all the numbers together, and all the variables

-5F^2-7F+300=0

a = -5; b = -7; c = +300;
Δ = b2-4ac
Δ = -72-4·(-5)·300
Δ = 6049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{6049}}{2*-5}=\frac{7-\sqrt{6049}}{-10}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{6049}}{2*-5}=\frac{7+\sqrt{6049}}{-10}
$